Passwords

[Unregistered]

Can someone help please? I want to write a password function using only ANSI/ISO C so that it does not echo what the user types. Like on Linux but is OS independent, so it will work on dos or any other OS. I know you can with CONIO.H but this is not in the standard. If theres a way please help if not can you please say so. Any help would be appreciated.

[Unregistered]

There is no OS independent answer to this question.

[Witch_King]

Start writing some code than someone can help you out. It's true, conio.h is not in the definition of C, but you can start by using stdio.h functions like scanf and printf.

[ggs]

curses/ncurses/pcurses/pdcurses

search for these libraries.

[Unregistered]

Im not sure what all that assembly language stuff means?

[Feelin' Silly]

I didn't realize at the time but that stuff at the end of your post is at the end of all your posts. I feel stupid

[Witch_King]

I posted this code on the C++ board. Thread with the word astericks in it, 2nd page. Question asked by NOOb

[Witch_King]

#include<stdio.h>
#include<conio.h>
int main()
{
	char buffer[12];
	int i, ch;

	printf("Enter a password (10 alphanumeric sequenc max):\n" );
	printf("Password: ");
	
	/* Read password but no larger than 10 characters */
	for( i = 0; i < 10 ; i++ )
	{
		//get character
		ch = _getch();
		//if user enters newline than quit
		if(ch == '\r' || ch == '\n') break;
		//if user enters backspace
		if(ch == '\b')
		{
			//if there are no preceeding letters
			if(i == 0) 
			{
				--i;
				continue;
			}else //if there are preceeding letters
			{
				printf("\b%c\b",' ');
				i-=2;
			}
		}else //no backspace was entered
		{
			putc('*',stdout);
			buffer[i] = (char)ch;
	
		}
	}
	/* Terminate string with null character: */
	buffer[i] = '\0';
	printf( "\n%s", buffer);

	return 0;
}

[Unregistered]

Thanks for that!