A simple double linked list using OOP techniques source code

This snippet submitted by Ali Nawkhas Murad on 2012-03-10. It has been viewed 30072 times.
Rating of 5.5 with 141 votes

//An example of a simple double linked list using OOP techniques
#include <iostream>
using namespace std;

struct Node
{
  double value;
  Node *N,*P;
  Node(double y)
  {
      value = y;
      N = P = NULL;
  }
};

class doubleLinkedList
{
  Node *front;
  Node *back;
  public:
  doubleLinkedList()
  {  front = NULL; back = NULL; }
  ~doubleLinkedList(){ destroyList();}
  void appendNodeFront(double x);
  void appendNodeBack(double x);
  void dispNodesForward();
  void dispNodesReverse();
  void destroyList();
};

void doubleLinkedList::appendNodeFront(double x)
  {
        Node *n = new Node(x);
        if( front == NULL)
        {
            front = n;
            back = n;
        }
        else
        {
            front->P = n;
            n->N = front;
            front = n;
        }
  }
  void doubleLinkedList::appendNodeBack(double x)
  {
        Node *n = new Node(x);
        if( back == NULL)
        {
            front = n;
            back = n;
        }
        else
        {
            back->N = n;
            n->P = back;
            back = n;
        }

  }

  void doubleLinkedList::dispNodesForward()
  {
      Node *temp = front;
      cout << "\n\nNodes in forward order:" << endl;
      while(temp != NULL)
      {
         cout << temp->value << "   " ;
         temp = temp->N;
      }
  }
  void doubleLinkedList::dispNodesReverse()
  {
      Node *temp = back;
      cout << "\n\nNodes in reverse order :" << endl;
      while(temp != NULL)
      {
         cout << temp->value << "   " ;
         temp = temp->P;
      }
  }
void doubleLinkedList::destroyList()
{
    Node *T = back;
    while(T != NULL)
    {
        Node *T2 = T;
        T = T->P;
        delete T2;
    }
    front = NULL;
    back = NULL;
}
int main()
{
    doubleLinkedList *list = new doubleLinkedList();
    //append nodes to front of the list
    for( int i = 1 ; i < 4 ; i++)
    list->appendNodeFront(i*1.1);

    list->dispNodesForward();
    list->dispNodesReverse();

    //append nodes to back of the list
    for( int i = 1 ; i < 4 ; i++)
    list->appendNodeBack(11.0 - (1.1 * i));
    cout << endl << endl;
    list->dispNodesForward();
    list->dispNodesReverse();

    cout << endl << endl;
    delete list;
    return 0;
}

/* Program's output
Nodes in forward order:
3.3   2.2   1.1

Nodes in reverse order :
1.1   2.2   3.3



Nodes in forward order:
3.3   2.2   1.1   9.9   8.8   7.7

Nodes in reverse order :
7.7   8.8   9.9   1.1   2.2   3.3
*/




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