This C code assigns codes to a maximum of 10 chars source code

This snippet submitted by Abhishek H.Dwivedi on 2005-02-17. It has been viewed 6073 times.
Rating of 2.9 with 33 votes

#include<stdio.h>
#include<conio.h>
#include<math.h>

int temp,i,j,col=0,n=100,count=0,b[10][2];
float a[10],sum=100;
char c[10][10];
void main()
{
    void part(int,int);
    clrscr();
    printf("Enter number of characters ");
    while(n>10)
    {
	printf("(Not more than 10) ");
	scanf("%d",&n);
    }
    while(sum>1)
    {
	printf("Enter their probabilities of occurences\n");
	sum=0;
	for(i=1;i<=n;i++)
	{
	    printf(".");
	    scanf("%f",&a[i]);
	    while(a[i]>=1)
		a[i]=a[i]/10;
	    sum=sum+a[i];
	    if(sum>1)
		break;
	}
	if(sum>1)
	    printf("Sum of probabilities must be less than or equal to 1 !\n");
    }
    for(i=0;i<10;i++)
    {
	for(j=0;j<10;j++)
	    c[i][j]='*';
    }
    for(i=0;i<n;i++)
    {
	for(j=0;j<n;j++)
	{
	    if(a[j]<a[j+1])
	    {
		temp=a[j];
		a[j]=a[j+1];
		a[j+1]=temp;
	    }}}
	    printf("\n\n");
	    part(1,n);
	    printf("The codes are \n");
	    for(i=0;i<n;i++)
	    {
		for(j=0;j<10;j++)
		    printf("%c ",c[i][j]);
		printf("\n");
	    }
	    getch();
}
void part(int low,int high)
{
    int min=100,k,z,sum=0,dif,sum1=0,l=0;
    z=(high-low);
    z=abs(z);
    for(j=0;j<10;j++)
	for(i=0;i<2;i++)
	    b[j][i]=0;
    if(z>1)
    {
	count++;
	for(i=low-1;i<high;i++)
	    sum=sum+a[i];
	sum1=a[low-1];
	sum=sum-a[low-1];
	for(i=low;i<=high;i++)
	{
	    dif=sum-sum1;
	    sum1=a[i]+sum1;
	    sum=sum-a[i];
	    b[l][0]=abs(dif);
	    b[l][1]=i;
	    l++;
	}
	for(i=0;i<l;i++)
	    if(min>b[i][0])
	    {
		min=b[i][0];
		k=b[i][1];
	    }
	for(i=low-1;i<k;i++)
	    c[i][col]='0';
	for(i=k;i<high;i++)
	    c[i][col]='1';
	col++;
	part(low,k);
	part(k+1,high);
    }
    else
    {
	c[low][col]='1';
	c[high][col]='0';
	if(c[high+1][col]=='*'&&high<=9)
	    while(c[high+1][col]=='*')
		col--;
	col++;
    }
}




More C and C++ source code snippets

Add a snippet!