dynamically create and initialise 4d array source codeThis snippet submitted by G.Watt.Porteous on 2012-06-27. It has been viewed 17217 times.Rating of 5.3 with 138 votes #include <stdio.h> #include <stdlib.h> /********************************************************/ /* */ /* */ /* Initialise a 4-d array with successive numbers. */ /* */ /* */ /* The array is formed dynamically using malloc. */ /* */ /* g.watt.porteous (gemera) 17th June 2012 */ /* */ /* [email protected] */ /********************************************************/ #define d4 4 #define d3 4 #define d2 4 #define d1 4 void initarr(int ****array,int hyp_sz,int plane_sz,int row_sz,int col_sz); int main(void) { int ****array; int hyp_sz = d4,plane_sz = d3,row_sz = d2,col_sz = d1; int h,i,j; array = malloc(hyp_sz * sizeof(int***)); if (array == NULL) { fprintf(stderr,"Out Of Memory"); exit(EXIT_FAILURE); } for(h = 0;h < hyp_sz;h++) { array[h] = malloc(plane_sz * sizeof(int**)); if(array[h] == NULL) { fprintf(stderr,"Out Of Memory"); exit(EXIT_FAILURE); } for(i = 0;i < plane_sz;i++) { array[h][i] = malloc(row_sz * sizeof(int*)); if(array[h][i] == NULL) { fprintf(stderr,"Out Of Memory"); exit(EXIT_FAILURE); } for(j = 0;j < row_sz;j++) { array[h][i][j] = malloc(col_sz * sizeof(int)); if(array[h][i][j] == NULL) { fprintf(stderr,"Out Of Memory"); exit(EXIT_FAILURE); } } } } printf("\n\n"); initarr(array,hyp_sz,plane_sz,row_sz,col_sz); // initialise and display array getchar(); return 0; } void initarr(int ****array,int hyp_sz,int plane_sz,int row_sz,int col_sz) { int g,h,i,j; for(g = 0 ;g < hyp_sz; g++) { for(h = 0;h < plane_sz; h++) { for(i = 0;i < row_sz; i++) { for(j = 0;j < col_sz; j++) { array[g][h][i][j] = (g*plane_sz*row_sz*col_sz) + (h*row_sz*col_sz) + (i*col_sz )+ j + 1; printf("%5d", array[g][h][i][j]); } printf("\n"); } printf("\n"); } printf("\n\n"); } } More C and C++ source code snippets |