Integer to English Practice Problem - Solution

Integer to English String Practice Problem Solution

```#include <string>
#include <iostream>

using namespace std;

string num_to_text[] = { "", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };

string tens_to_text[] = { "", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" };

string power_to_text[] = { "", "thousand", "million", "billion" };

{
if ( ans == "" )
{
return "";
}
return " " + ans;
}

string translateHundred (int hundred_chunk)
{
// handle special cases in the teens
if ( hundred_chunk < 20 ) {
return num_to_text[ hundred_chunk ];
}
int tens = hundred_chunk / 10;
int ones = hundred_chunk % 10;
return tens_to_text[ tens ] + padIfNeeded( num_to_text[ ones ] );
}

string translateThousand (int thousand_chunk)
{
if ( thousand_chunk < 100 )
{
return translateHundred( thousand_chunk );
}
else
{
int hundreds = thousand_chunk / 100;
int hundred_chunk = thousand_chunk % 100;
return num_to_text[ hundreds ] + " hundred" + padIfNeeded( translateHundred( hundred_chunk ) );
}
}

int main()
{
int n;
cin >> n;
string number;
bool is_negative = false;
if ( n < 0 )
{
is_negative = true;
n *= -1;
}

int chunk_count = 0;
while ( n > 0 )
{
if ( n % 1000 != 0 ) {
number = translateThousand( n % 1000 ) + padIfNeeded( power_to_text[ chunk_count ] + padIfNeeded( number ) );
}
n /= 1000;
chunk_count++;
}
if ( number == "" )
{
number = "zero";
}
if ( is_negative )
{
number = "negative " + number;
}
cout << number << endl;
}
```