# Tutorials - XOR Challenge

#### Solution to XOR Variable Swapping

So you have two variables, a and b; we'll assign a to be 5, and b to be 10. We want to store the value of a in b, and the value of b in a, but without using a temporary variable.
```int a, b;
a = 5;
b = 10;
```
We can do this using bitwise XOR remembering the principle that two applications of XOR to a variable will "cancel out". Here's a function that will take pointers to two variables and flip them. For clarity, I'll refer to the original values stored in a and b as a_orig and b_orig. Originally, *a and *b will be a_orig and b_orig, but this will change over time.
```void flip(int *a, int *b)
{
*a = *a ^ *b;
// Now, we can recover *a_orig by applying *a XOR *b_orig
*b = *a ^ *b;
// So we have the following situation:
// The value originally stored in *a, a_orig, is now in *b
// and *a still stores a_orig ^ b_orig
// This means that we can recover the value of b_orig by applying
// the XOR operation to *a and a_orig.  Since *b stores a_orig...
*a = *a ^ *b
}
```